A passenger of a train moving uniformly at a speed of 54 km / h sees for 60 seconds another train with

| September 3, 2021 | education

A passenger of a train moving uniformly at a speed of 54 km / h sees for 60 seconds another train with a length of 300 m, which is moving along an adjacent track in the same direction at a higher speed. Find the speed of the second train.

Initial data: V1 (constant speed of the passenger’s train) = 54 km / h (in SI V1 = 15 m / s); t (time of observation by a passenger of a train on a neighboring track) = 60 s; L (train length on the adjacent track) = 300 m; the directions of the trains are the same.

The speed of the train on the adjacent track can be expressed from the formula: t = L / (V2 – V1), whence L / t = V2 – V1 and V2 = L / t + V1.

Let’s calculate: V2 = 300/60 + 15 = 5 + 15 = 20 m / s.

Answer: The speed of the train on the adjacent track is 20 m / s.



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