A passenger standing motionless on the escalator descends for 4 minutes, and if he walks along the escalator for 45
| September 1, 2021 | education
A passenger standing motionless on the escalator descends for 4 minutes, and if he walks along the escalator for 45 seconds, how long does it take for the passenger to descend the stationary escalator.
Given: t1 (time of descent of a stationary passenger on an escalator) = 4 min (240 s); t2 (time of descent of a moving passenger) = 45 s.
1) Let us express the passenger’s own speed relative to the escalator speed: S = V1 * t1 = (V1 + V2) * t2 = V1 * t2 + V2 * t2.
V1 * 240 = V1 * 45 + V2 * 45.
V2 = (240V1 – 45V1) / 45 = 4.33V1.
2) Determine the time of descent along a stationary escalator: V1 * t1 = V2 * t3.
V1 * t1 = 4.33V1 * t3.
t3 = V1 * t1 / 4.33V1 = 240 / 4.33 = 55.4 s.
Answer: The passenger will descend in 55.4 seconds.
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