A passenger train departed from M to N at a speed of 60 km / h. and 10 minutes later, an electric train followed

A passenger train departed from M to N at a speed of 60 km / h. and 10 minutes later, an electric train followed him out of M, passing 85 km / h. At what distance from station N will the second train catch up with the first if the length of the track MN is 40 km?

The speed of a passenger train is 60 km / h (1 km / min), let the time of its movement be x. So he drove 1 * x. Following the passenger train, an electric train departed, its speed is 85 km / h (1.42 km / min), it is known that the electric train left 10 minutes later than the passenger train, which means its travel time is x – 10. So it traveled 1.42 * (x – 10). The distance for them will be the same, since, according to the condition, the electric train caught up with the passenger train.

1.42 * (x – 10) = 1 * x

1.42x – 14.2 = x

1.42x – x = 14.2

0.42x = 14.2

x = 14.2 / 0.42

x = 34

So the passenger train traveled 34 minutes, let’s calculate how many kilometers it traveled during this time.

34 * 1 = 34 km.

If the total distance between MN is 40, we find at what distance from N, the electric locomotive caught up with the passenger train.

40 – 34 = 6 km.

Answer: At a distance of 6 km from N, an electric locomotive caught up with a passenger train.