A passenger train starts to move at an acceleration of 0.075 meters per second squared.

A passenger train starts to move at an acceleration of 0.075 meters per second squared. To what speed will it accelerate in 3min

Initial data: a (acceleration with which the passenger train starts to move) = 0.075 m / s2; t (acceleration duration) = 3 min (180 s); V0 (initial speed of the passenger train) = 0 m / s.

The speed to which the passenger train will accelerate is determined by the formula: V = V0 + a * t = a * t.

Calculation: V = 0.075 * 180 = 13.5 m / s.

Answer: In 3 minutes, a passenger train will accelerate to a speed of 13.5 m / s.