A passenger travels on a train with a speed v1 = 54 km / h. How long will the passenger see through the window

A passenger travels on a train with a speed v1 = 54 km / h. How long will the passenger see through the window a train overtaking 200 meters long, moving at a speed of 90 km / h.

These tasks: V1 (speed of the train in which the passenger is sitting) = 54 km / h (in SI V1 = 15 m / s); L (length of the overtaking train) = 200 m; V2 (speed of the overtaking train) = 90 km / h (in SI V2 = 25 m / s).

The time during which the passenger will observe the overtaking train is determined by the formula: t = S / V = L / (V2 – V1).

Let’s make a calculation: t = 200 / (25 – 15) = 200/10 = 20 s.

Answer: The passenger will watch the overtaking train for 20 seconds.



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