A passenger walking on a moving escalator goes up in 5 minutes, and on a stationary one in 8 minutes
| July 6, 2021 | education
A passenger walking on a moving escalator goes up in 5 minutes, and on a stationary one in 8 minutes. Determine the speed of the escalator if its length is 100 m.
t1 = 5 min = 300 s.
t2 = 8 min = 480 s.
S = 100 m.
Ve -?
When a person walks in the direction of movement of the escalator, he moves relative to the surface of the earth at a speed V1 = V + Ve, where V is the person’s own speed, Ve is the speed of the escalator.
t1 = S / V1 = S / (V + Ve).
Ve = S / t1 – V.
The time of lifting a person along a stationary escalator t2 is expressed by the formula: t2 = S / V.
V = S / t2.
Ve = S / t1 – S / t2.
Ve = 100 m / 300 s – 100 m / 480 s = 0.125 m / s = 0.13 m / s.
Answer: the speed of the escalator is Ve = 0.13 m / s.
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