A pedestrian left point A to point B at a speed of 4 km / h. After 45 minutes, another pedestrian left point B
| January 9, 2021 | education
A pedestrian left point A to point B at a speed of 4 km / h. After 45 minutes, another pedestrian left point B at a speed of 5 km / h towards him, pedestrians arrived at points A and B at the same time. Find the distance between points A and B.
1. We take the distance between points A and B as x.
2.x / 4 – time of movement of the first pedestrian from point A to point B.
x / 5 – time of movement of the second pedestrian from point B to point A.
The travel time of the second pedestrian is 15 minutes or 3/4 hours less than the first one, since he left later.
3. We compose and solve the equation:
x / 4 – x / 5 = 3/4;
x / 20 = 3/4;
4x = 60;
x = 15 km.
Answer: the distance between points A and B is 15 kilometers.
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