A pedestrian left the tourist parking lot A to parking lot B at 8.00 at a speed of 4 km / h. At 9.30 a cyclist left B

A pedestrian left the tourist parking lot A to parking lot B at 8.00 at a speed of 4 km / h. At 9.30 a cyclist left B to A to meet him. With what speed should he go to meet a pedestrian at 10.00, if the distance between three hundred parking lots is 15 km?

1. We take for x the speed with which the cyclist must ride to meet the traveler at 10 o’clock.

2. A traveler from the tourist base to the meeting point with a cyclist will take 10 hours – 8 hours = 2 hours. The cyclist will reach the meeting point in 10 hours – 9 hours 30 minutes = 30

minutes = 30/60 hours = 0.5 hours.

3. Let’s compose the equation:

0.5x + 4 x 2 = 15;

0.5x = 7;

x = 14 km / h.

Answer: The cyclist must travel at a speed of 14 km / h to meet the traveler at 10 o’clock.