A person at rest in 1 min. absorbs 0.0002 m3 of oxygen with a density of 1.43 kg / m3.

A person at rest in 1 min. absorbs 0.0002 m3 of oxygen with a density of 1.43 kg / m3. Determine the mass of oxygen a person needs per hour.

These tasks: t1 (the first time a person absorbs oxygen) = 1 min; V1 (volume of absorbed oxygen during time t1) = 0.0002 m3; t2 (second time) = 1 h = 60 min.

Reference values: according to the condition ρк (oxygen density) = 1.43 kg / m3.

The mass of oxygen required by a person per hour is determined by the formula: m = m1 * t2 = V1 * ρк * t2.

Let’s calculate: m = 0.0002 * 1.43 * 60 = 0.01716 kg (17.16 g).

Answer: For 1 hour, a person will need 17.16 g of oxygen.