A person can descend to a depth of 9m, calculate the water pressure on a person at this depth, the density of seawater is 1030.

h = 9 m.
g = 10 m / s ^ 2.
ρ = 1030 kg / m ^ 3.
R -?
The hydrostatic pressure P in a liquid is determined by the formula P = ρ * g * h, where ρ is the density of the liquid, g is the acceleration of gravity, h is the height of the liquid.
P = 1030 kg / m ^ 3 * 10 m / s ^ 2 * 9 m = 92,700 Pa.
Answer: a person is affected by a pressure of P = 92700 Pa.



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