A person descends on a parachute, moving evenly. The gravity of the parachutist with the parachute is 700 N.

A person descends on a parachute, moving evenly. The gravity of the parachutist with the parachute is 700 N. What is the force of air resistance?

Since, according to the condition of the problem, a person descending on a parachute moves uniformly, then his acceleration is equal to zero. Let us write Newton’s second law for the movement of a parachutist in order to find the force of air resistance: m * a = Ftyazh – Fsopr, where m * a is the resultant of all forces, Ftyaz is the force of gravity acting on the parachutist from the ground, Fsopr is the force of air resistance to its movement , it turns out 0 = FTyazh – Fsopr or Ftyazh = Fsopr. It is known that the gravity force of the parachutist together with the parachute Ftyazh = 700 N, then Fsopr = 700 N. Answer: the force of air resistance is 700 N.



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