A person in seawater with a density of 1030 kg / m3 at a depth of 2 meters experiences approximately pressure …
July 24, 2021 | education|
Initial data: ρ (density of sea water) = 1030 kg / m ^ 3; h (human immersion depth) = 2 m.
Reference values: g (acceleration due to gravity) = 9.81 m / s ^ 2.
The hydrostatic pressure of sea water per person can be determined from the following formula: P = ρ * g * h.
Let’s do the calculation:
P = 1030 * 9.81 * 2 = 20208.6 ≈ 20 kPa.
Answer: A person at a depth of 2 m will be affected by a hydrostatic pressure of 20 kPa.
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