A person pushes a 5 kg weight with a force of 100N, the force vector is directed vertically downward.

A person pushes a 5 kg weight with a force of 100N, the force vector is directed vertically downward. With what acceleration does the weight move during this point?

To find the value of the acceleration of the taken weight during the push, we will project all the forces onto the vertical axis: m * a = Ftol – Ft = Ftol – m * g, whence we express: a = (Ftol – m * g) / m.

Constants and variables: Ftol – push force of the weight (Ftol = 100 N); m is the mass of the weight (m = 5 kg); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: a = (Ftol – m * g) / m = (100 – 5 * 10) / 5 = 10 m / s2.

Answer: The acceleration of the taken weight during the push was 10 m / s2.