A person who slapped in the palm of his hand heard an echo after time t = 1s.

| May 9, 2021 | education

A person who slapped in the palm of his hand heard an echo after time t = 1s. At what distance S is the obstacle that reflected the sound? The speed of sound in air is v = 340 m / s.

t = 1 s.

Vsv = 340 m / s.

S1 -?

The clap of the hand travels to the obstacle, bounces off it, and travels back to the investigator who hears the echo of the clap.

In time t, the sound travels the path S, equal to double the distance to the obstacle S1: S = 2 * S1.

With uniform rectilinear motion, the path S traversed by the body is found by the product of the speed of motion Vsv and the time of its movement t: S = Vsv * t.

Vsv * t = 2 * S1.

The distance to the obstacle S1 will be determined by the formula: S1 = Vsv * t / 2.

S1 = 340 m / s * 1 s / 2 = 170 m.

Answer: the obstacle is at a distance of S1 = 170 m from the person.



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