A piece of ice 80 g is placed in a calorimeter containing 500 g of water at a temperature of 20 ° C

A piece of ice 80 g is placed in a calorimeter containing 500 g of water at a temperature of 20 ° C at a temperature of 0 ° C. How much heat must be given to the ice in order for it to melt completely?

Problem data: m1 (mass of water contained in the calorimeter) = 500 g (in SI m1 = 0.5 kg); t1 (water temperature) = 20 ºС; m2 (weight of added ice) = 80 g (m2 = 0.08 kg); t2 (ice temperature) = 0 ºС.

Constants: Cw (specific heat capacity of water) = 4200 J / (kg * ºС); λ (specific heat of melting of ice) = 3.4 * 10 ^ 5 J / kg.

The amount of heat that water will transfer to ice for melting: Q = m2 * λ.

Let’s perform the calculation: Q = 0.08 * 3.4 * 10 ^ 5 = 27,200 J (27.2 kJ).

Answer: Ice needs to transfer 27.2 kJ of heat.