A piece of ice taken at a temperature of -10 ° C was heated to the melting temperature and completely melted.
| April 19, 2021 | education
A piece of ice taken at a temperature of -10 ° C was heated to the melting temperature (tp 0 ° C) and completely melted. How much heat was needed? L = 33 × 10 ^ 4C = 2100 Ice mass 3 kg.
Initial data: t0 (initial ice temperature) = -10 ºС; m (ice mass) = 3 kg.
Reference data: according to condition C (specific heat of ice) = 2100 J / (kg * K); λ (specific heat of melting of ice) = 33 * 10 ^ 4 J / kg; tmelt (ice melting temperature) = 0 ºС.
Q = Q1 (heating ice to the melting point) + Q2 (melting ice) = С * m * (tmelt. – t0) + λ * m.
Let’s perform the calculation:
Q = 2100 * 3 * (0 – (-10)) + 33 * 10 ^ 4 * 3 = 1053000 J = 1.053 MJ.
Answer: It took 1.053 MJ of heat.
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