A piece of ice weighing 10 g falls in the air with an acceleration of 8 meters per second. find the force of air resistance.

Problem data: m (mass of a piece of ice) = 10 g (in SI m = 0.01 kg); a (particle acceleration) = 8 m / s2.

Reference values: according to the condition g (acceleration of gravity) = 9.8 m / s2.

Let us express the air resistance force from the equality: m * a = Ft – Fcopr, whence Fcopr = Ft – m * a = m * g – m * a = m * (g – a).

Let’s perform the calculation: Fcopr = 0.01 * (9.8 – 8) = 0.018 N.

Answer: The force of air resistance to the movement of a hail of ice is 0.018 N.