A piece of ice weighing 5 kg has a temperature of -10 degrees. How much heat needs to be transferred to it to turn ice into water?

univerkov | February 13, 2021 | education

Initial data: m (ice mass) = 5 kg; t0 (initial ice temperature) = -10 ºС.

Reference data: tmelt (temperature of transition of ice into water) = 0 ºС; C (specific heat of ice) = 2100 J / (kg * K); λ (specific heat of melting of ice) = 340 * 10 ^ 3 J / kg.

The required amount of heat: Q = Q1 (heating) + Q2 (transformation into water) = C * m * (tm. – t0) + λ * m = m * (C * (tm. – t0) + λ).

Q = 5 * (2100 * (0 – (-10)) + 340 * 10 ^ 3) = 1805000 J = 1.805 MJ.

Answer: 1.805 MJ of heat must be transferred to ice.

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