A piece of iron weighing 20 kg was heated from 10 ° to 90 ° C. How much heat was

A piece of iron weighing 20 kg was heated from 10 ° to 90 ° C. How much heat was transferred to the iron? (specific heat of iron c = 460 J / kg • C)

Problem data: m (mass of the heated piece of iron) = 20 kg; t1 (initial temperature) = 10 ºС; t2 (final temperature of the taken piece of iron) = 90 ºС.

Reference values: according to the condition Сж (specific heat capacity of iron) = 460 J / (kg * ºС).

The amount of heat that was transferred to a piece of iron during heating is calculated by the formula: Q = Szh * m * (t2 – t1).

Calculation: Q = 460 * 20 * (90 – 10) = 460 * 20 * 80 = 736 * 10 ^ 3 J (736 kJ).

Answer: 736 kJ of heat was transferred to a piece of iron.