A piece of iron weighing 500 g is immersed in kerosene. Determine the pulling out force

A piece of iron weighing 500 g is immersed in kerosene. Determine the pulling out force if the density of iron is 7900 kg / m3, the density of kerosene is 820 kg / m3.

To calculate the magnitude of the buoyancy force acting on a given piece of iron, we apply the formula: Fa = ρker * g * V = ρker * g * m / ρzh.

Data: ρker – kerosene density (according to the condition ρker = 820 kg / m3); g – acceleration of gravity (g = 9.81 m / s2); m is the mass of a piece of iron (m = 500 g = 0.5 kg); ρzh – density of iron (according to the condition ρzh = 7900 kg / m3).

Let’s make a calculation: Fa = ρker * g * m / ρzh = 820 * 9.81 * 0.5 / 7900 ≈ 0.51 N.

Answer: The buoyancy force acting on a given piece of iron is 0.51 N.