A piece of metal weighs 7.8 N in air, and 6.8 N in water. Find the volume of this piece.

Let us determine with the help of how many Newtons the Archimedean force will be expressed, which acts on a piece of metal when it is immersed in water, when from the condition of the task we know that this piece weighs 7.8 N in air, while when immersed in water 6 , 8 N:

7.8 – 6.8 = 1.

Let us determine through what number of cubic meters it will be possible to express the volume of this piece, when it is known that the density of water is roughly 1000 kg / m3:

V = 1: (1000 * 10) = 0.0001.

Answer: The volume of this piece is 0.0001 m3.