A pine ball was immersed in the water, determine the Archimedean force acting on the ball
A pine ball was immersed in the water, determine the Archimedean force acting on the ball, if the density of the pine is 400 kg / m3, and its weight is 1.7N.
Data: P is the weight of the specified pine ball (P = 1.7N).
Const: ρw – water density (approx. Ρw = 10 ^ 3 kg / m3); ρс – density of the sphere, pine (according to the condition ρс = 400 kg / m3).
To find out the force of Archimedes, which should act on the specified pine ball, we use the formula: FA = ρw * g * Vsh.
a) Full immersion: FA = ρw * g * Vsh = ρw * g * msh / ρs = ρw * g * Vsh = ρw * g * P / (ρs * g) = ρw * P / ρs = 10 ^ 3 * 1 .7 / 400 = 4.25 N.
b) Equilibrium (only a part of the ball under water): FA = ρw * g * Vlim = ρw * g * Vsh * ρs / ρw = g * P / (ρs * g) * ρs = P = 1.7 N (Archimedes’ law ).
Answer: When the specified pine ball is completely immersed, the Archimedes force is 4.25 N, in the case of equilibrium – 1.7 N.