A pipe weighing 14 kg lies on the ground. How much force must be applied to one end of the pipe in order to lift it slightly.

To determine the minimum force required to lift one of the ends of the taken pipe, we use the rule of moments: Fт * l1 = F * l2; m * g * l / 2 = F * l, whence we express: F = m * g / 2.

Variables and constants: m is the mass of the taken pipe (m = 14 kg); g – acceleration due to gravity (g = 9.81 m / s2).

Calculation: F = m * g / 2 = 14 * 9.81 / 2 = 68.67 N.

Answer: A force of at least 68.67 N. must be applied to one of the ends of the taken pipe.



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