A plastic bottle holds 1 liter of kerosene. Will it fit 1 kg of water? (water density is 1000 kg / m3, kerosene 800 kg / m3)

This is a tricky task, that is, here you just need to calculate the volume of water weighing 1 kg.

1) Density of water p = 1000 kg / m ^ 3, P = 1 kg (water weight).

2) According to the formula, weight (mass) m = p * V, whence the volume of water V = m / p = 1kg / 1000kg / m ^ 3 = 1 kg / 1000 kg / m ^ 3 = 0.001 m ^ 3 = 1 liter.

That is, we got that the volume of occupied water with a mass of 1 kg is equal to 1 liter, and it will fit into a bottle with this volume.

3) But the mass of 1 liter of kerosene will be less than the weight of 1 liter of water, since mk = pk * Vk = 800 kg / m ^ 3 * 0.001 m ^ 3 = 0.8 kg.

Answer: fits in a 1 liter bottle.