A plastic bottle holds 1 liter of kerosene. Will it hold 1 kg of water?

In order for 1 kg of water to fit into the plastic bottle under consideration, the inequality must be fulfilled: Vker ≥ mwater / ρwater.

Constants and variables: Vker – the volume of kerosene in the considered plastic bottle (Vker = 1 l = 10 ^ -3 m3); mwater is the mass of water (mwater = 1 kg); ρwater is the density of water (ρwater = 10 ^ 3 kg / m3).

Calculation: Vker ≥ mvolume / ρvoltage.

10 ^ -3 ≥ 1/10 ^ 3.

10 ^ -3 m3 ≥ 10 ^ -3 m3 (correct).

Answer: 1 kg of water can fit in the plastic bottle in question.



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