A plasticine ball weighing 2 kg, moving at a speed of 6 m / s, hits a resting ball weighing 4 kg.
| July 13, 2021 | education
A plasticine ball weighing 2 kg, moving at a speed of 6 m / s, hits a resting ball weighing 4 kg. Determine the speed of their joint movement.
Initial data: m1 (mass of the first plasticine ball) = 2 kg; V1 (initial speed of the first plasticine ball) = 6 m / s; m2 (mass of the second plasticine ball) = 4 kg; V2 (initial velocity of the second plasticine ball) = 0 m / s.
The speed of joint motion of plasticine balls is determined from the law of conservation of momentum: m1 * V1 + m2 * V2 = m1 * V1 + 0 = (m1 + m2) * U.
U = m1 * V1 / (m1 + m2) = 2 * 6 / (2 + 4) = 2 * 6/6 = 2 m / s.
Answer: The speed of the joint movement is 2 m / s.
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