A platform with a mass of 20 tons, moving along a horizontal path at a speed of 0.5 m / s, overtakes

| June 25, 2021 | education

A platform with a mass of 20 tons, moving along a horizontal path at a speed of 0.5 m / s, overtakes another platform with a mass of 10 tons, having a speed of 2 m / s. Determine the speed after an absolute inelastic impact?

mp1 = 20 t = 20,000 kg.

mp2 = 10 t = 10000 kg.

Vp1 = 0.5 m / s.

Vp2 = 2 m / s.

V “-?

An absolutely inelastic impact is an interaction in which bodies stick together and begin to move together at the same speed.

Let’s write down the law of conservation of momentum: mp1 * Vp1 + mp2 * Vp2 = (mp1 + mp2) * V “.

The speed of platforms after interaction will be determined by the formula:

V “= (mp1 * Vp1 + mp2 * Vp2) / (mp1 + mp2).

V “= (20,000 kg * 0.5 m / s + 10,000 kg * 2 m / s) / (20,000 kg + 10,000 kg) = 1 m / s.

Answer: the speed of the platforms after an absolutely inelastic impact will become V “= 1 m / s.



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