A point D is marked inside an equilateral triangle ABC such that the angle BAD is equal to the angle BCD = 15 degrees.

A point D is marked inside an equilateral triangle ABC such that the angle BAD is equal to the angle BCD = 15 degrees. Find the ADC angle.

angle A = angle C = 60 degrees
angle BAD- part of angle A = 15 degrees
angle DAC = angle A- angle BAD = 60-15 = 45 degrees.
The DCA is respectively 45 degrees.
angle DАС + angle АDС + angle DСА = 180
angle ADС = 180-angle DАС-angle DСА = 180-45-45 = 90
Answer: 90



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