A point electric charge of 2.2 nL creates a field, the intensity of which at a distance of 6 cm
| February 12, 2021 | education
A point electric charge of 2.2 nL creates a field, the intensity of which at a distance of 6 cm from the charge 2.5 kV / m. Determine the dielectric constant of the medium.
To determine the dielectric constant of a given medium, we will use the formula: E = k * q / (ε * R ^ 2), whence we express: ε = k * q / (E * R ^ 2).
Constants and variables: k – proportionality coefficient (k = 9 * 10 ^ 9 m / F); q – the value of the charge (q = 2.2 nC = 2.2 * 10 ^ -9 C); E – field strength (E = 2.5 kV / m = 2500 V / m); R is the distance to the charge (R = 6 cm = 0.06 m).
Calculation: ε = k * q / (E * R ^ 2) = 9 * 10 ^ 9 * 2.2 * 10 ^ -9 / (2500 * 0.062) = 2.2.
Answer: The dielectric constant of a given medium is 2.2.
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