A projectile weighing 2 kg, flying at a speed of 1512 km / h parallel to the rails
| July 17, 2021 | education
A projectile weighing 2 kg, flying at a speed of 1512 km / h parallel to the rails, strikes a stationary platform with sand weighing 800 kg. How fast will the platform move?
Initial data: m1 (projectile mass) = 2 kg; V1 (speed at which the projectile flew) = 1512 km / h; m2 (platform weight) = 800 kg; V2 (initial platform speed) = 0 m / s.
SI system: V = 1512 km / h = 420 m / s.
The speed at which the platform will move after being hit by a projectile can be calculated using the law of conservation of momentum: m1 * V1 + m2 * V2 = (m1 + m2) * V, whence V = m1 * V1 / (m1 + m2).
Calculation: V = 2 * 420 / (2 + 800) ≈ 1.05 m / s.
Answer: The platform will start moving at a speed of 1.05 m / s.
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