A projectile weighing 20 kg flies out of the gun barrel at a speed of 500 m / s.

A projectile weighing 20 kg flies out of the gun barrel at a speed of 500 m / s. Determine the average force of the pressure of the propellant gases on the projectile if the barrel length is 4 m.

To find the force of pressure of powder gases on a given projectile, we will use the equality: ΔEk = A; m * V ^ 2/2 = F * l, whence we express: F = m * V ^ 2 / 2l.

The values of the variables: m is the mass of the projectile (m = 20 kg); V – speed of departure from the gun barrel (V = 500 m / s); l is the length of the gun barrel (l = 4 m).

Let’s perform the calculation: F = m * V ^ 2 / 2l = 20 * 500 ^ 2 / (2 * 4) = 625 * 10 ^ 3 J (625 kJ).

Answer: On a given projectile, a force of pressure of powder gases of 625 kJ acted.