A projectile weighing 90 kg was shot from a gun weighing 9 tons in a horizontal direction

A projectile weighing 90 kg was shot from a gun weighing 9 tons in a horizontal direction, which acquired a speed of 300 m / s relative to the ground. What speed did the gun acquire?

Given:

m1 = 90 kilograms is the mass of the projectile;

v1 = 300 m / s – projectile speed relative to the ground;

m2 = 9 tons = 9000 kilograms – the mass of the gun from which the projectile flew.

It is required to determine v2 (m / s) – the speed of the gun relative to the ground.

To determine the speed of the gun relative to the ground, you need to use the following formula (the law of conservation of momentum):

m1 * v1 = m2 * v2;

v2 = m1 * v1 / m2 = 90 * 300/9000 = 27000/9000 = 27/9 = 3 meters per second.

Answer: the gun has acquired a speed equal to 3 meters per second.