A pulley with a radius of 30 cm makes 120 rpm. Determine the period of rotation, the linear speed of the points lying

A pulley with a radius of 30 cm makes 120 rpm. Determine the period of rotation, the linear speed of the points lying on the circumference of the pulley. What path will one of these points take in 1 minute?

R = 30 cm = 0.3 m.
v = 120 rpm = 2 rpm = 2 Hz.
t = 1 min = 60 s.
L -?
V -?
The frequency of rotation v is the number of complete rotations per unit of time, that is, in 1 second.
The frequency v = 2 Hz means that the body makes 2 complete revolutions in 1 second.
The traversed path L is expressed by the formula: L = t * 2 * L1, where L1 is the circumference.
L1 = 2 * P * R, where P is the number pi, R is the radius of the circle.
L = 4 * P * R * t.
L = 4 * 3.14 * 0.3 m * 60 s = 226 m.
The speed of movement of any point of the pulley V is found by the formula: V = L1 / T = L1 * v = 2 * P * R * v.
V = 2 * 3.14 * 0.3 m * 2 Hz = 3.77 m / s.
Answer: the linear speed is V = 3.77 m / s, the point has traveled the path L = 226 m.



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