A pump with a 25 kW motor, lifts 1000 kg of water to a height of 100 m in 3 hours.
| April 27, 2021 | education
A pump with a 25 kW motor, lifts 1000 kg of water to a height of 100 m in 3 hours. determine the efficiency of the pumping station.
Useful work performed by the pump during time t:
A = M g H,
where M is the mass of water, M = 1000 kg; g – acceleration of gravity, g = 9.8 m / s2; Н – water rise height, Н = 100 m.
Net pump power:
Np = A / t,
where t is the pump operation time, t = 3 h = 10800 s.
Pump efficiency:
η = Nп / N = M g H / (N t),
where N is the engine power, N = 25 kW = 25000 W.
Substitute the values in SI units:
η = 1000 × 9.8 × 100 / (25000 × 10800) = 0.0036 = 0.36%.
Answer: The efficiency is 0.36%.
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