A pump with a capacity of 50 kW from a mine 150 m deep must pump out 200 m ^ 2 of water.

A pump with a capacity of 50 kW from a mine 150 m deep must pump out 200 m ^ 2 of water. Express in minutes how much it will pump out water.

The work of gravity is equal to the potential energy of water at the level h:
Athlete = mg (h1 – h2) = -mgh
Let’s write down:
Avn = – Atiazh = mgh
Let’s write down the power and express the time:
N = Avn / t
t = Avn / N = mgh / N
m = p * V
Substitute in the time formula:
t = pVgh / N
t = (10 ^ -9 * 2 * 10 ^ 2 * 10 * 150) / 50 * 10 ^ 3 = 6000 (c)
t = 100 (min)
Answer: t = 100 (min)