A quadrilateral ABCD is inscribed in a circle, angle A = 102, angle B = 47.

A quadrilateral ABCD is inscribed in a circle, angle A = 102, angle B = 47. Find the degree measure of the larger of the other two angles.

By the property of a quadrilateral inscribed in a circle, the sum of its opposite angles is 180.

Angle ABC + ADC = 180.

ADC = 180 – 47 = 133.

Angle BAD + BCD = 180.

ВСD = 180 – 102 = 78.

Answer: The larger angle is 133.



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