A railway car weighing 10^4 kg, moving at a speed of 25 m / s, collides with a stationary car weighing 1.5 * 10 ^ 4 kg
| March 10, 2021 | education
A railway car weighing 10^4 kg, moving at a speed of 25 m / s, collides with a stationary car weighing 1.5 * 10 ^ 4 kg. How fast will the cars move if the coupling is triggered between them?
Initial data: m1 (mass of a moving railroad car) = 10 ^ 4 kg; V1 (speed of the car to the coupling) = 25 m / s; m2 (mass of a stationary car) = 1.5 * 10 ^ 4 kg.
The speed of two cars after coupling is determined using the law of conservation of momentum: (m1 + m2) * V1.2 = m1 * V1, whence V1.2 = m1 * V1 / (m1 + m2).
Calculation: V1.2 = 10 ^ 4 * 25 / (10 ^ 4 + 1.5 * 10 ^ 4) = 10 m / s.
Answer: After the coupling is triggered, the cars will start moving at a speed of 10 m / s.
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