A ray in air falls at an angle of 24 degrees onto the surface of a substance, the refractive index

A ray in air falls at an angle of 24 degrees onto the surface of a substance, the refractive index of which is 1.33, while the angle of refraction is y?

Data: α – angle of incidence of the specified beam (α = 24º); n1.2 is the refractive index of the surface of the substance (n1.2 = 1.33).

To find out the desired angle of refraction of the specified ray, we use the formula: n1.2 = sinα / sinγ, from where we express: sinγ = sinα / n1.2 and γ = arcsin (sinα / n1.2).

Let’s calculate: γ = arcsin (sinα / n1.2) = arcsin (sin 24º / 1.33) = arcsin 0.3058 ≈ 17.8º.

Answer: The required angle of refraction of the specified ray is 17.8º.