A ray is drawn from the apex of the angle, perpendicular to its bisector and forming an acute

A ray is drawn from the apex of the angle, perpendicular to its bisector and forming an acute angle equal to 40 ° with the side of this angle. Find the value of the given

Let BAC be the desired angle. We put point E on the bisector of the angle, point F on the ray, which is perpendicular to it.
Then we write the problem condition as follows: EAF = 90, CAF = 40
EAC = EAF – CAF = 90 – 40 = 50
EAB = EAC = 50 since AE is bisector
BAC = EAC + EAB = 100
Answer: 100 degrees.