A ray OK is drawn inside the corner MON so that ∠MOK = 22 ° and ∠KON = 44 °.

A ray OK is drawn inside the corner MON so that ∠MOK = 22 ° and ∠KON = 44 °. What part of the MON angle is the MOK angle?

The conducted ray OK formed two angles: MOC and KON, the sum of the degree measures of which gives us the angle MON:
∠ MON = ∠ MOK + ∠ KON = 22 ° + 44 ° = 66 °.
The angle MON is the whole integer, the angle MOC is its part, we find what part of the whole angle is the MOC:
∠ MOK / ∠ MON = 22 ° / 66 ° = 1/3.
Answer: The MOK angle is 1/3 of the MON angle.



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