A rectangle has a length 5 times greater than its width and 200 meters more than its width, find its area

Let us denote the length of the rectangle by the letter A, and the width by the letter B. In accordance with the data of the problem, we will compose a system of linear equations, which we will subsequently solve:

A = 5 x B;

A – B = 200.

Substitute the value for A from the first equation into the second:

5 x B – B = 200;

4 x B = 200;

B = 50 (m).

Now we can find out the length of our rectangle:

A = 5 x 50;

A = 250 (m).

Knowing the length and width of our rectangle, you can easily calculate its area:

250 x 50 = 12500 (m²).

Answer: The area of this rectangle is 12,500 square meters.



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