A rectangle is inscribed in a circle with a radius of 10 cm, one side of which is 14 cm. Find the area of the rectangle.

The diagonal of the ВD of the rectangle passes through the center of the circumscribed circle and is equal to its diameter, then BC = 2 * OB = 2 * R = 2 * 10 = 20 cm.

From the right-angled triangle of the ВСD, according to the Pythagorean theorem, we determine the length of the СD leg.

СD ^ 2 = ВD ^ 2 – BC ^ 2 = 400 – 196 = 204.

СD = √204 = 2 * √51 cm.

Determine the area of the rectangle.

Savsd = BC * СD = 14 * 2 * √51 = 28 * √51 cm2.

Answer: The area of the rectangle is 28 * √51 cm2.



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