A rectangle with sides of 55 cm and 1010 cm was cut into two squares. What is the sum of the perimeters

A rectangle with sides of 55 cm and 1010 cm was cut into two squares. What is the sum of the perimeters of the resulting squares?

First we need a rectangle with sides, 55 cm and 1010 cm, divided into two squares.
Since a square has all sides equal, it means that we will have squares with sides of 55 cm.
Now, to calculate the sum of the perimeters of the resulting squares.
We first need to calculate the perimeter of one square, and then multiply it by 2.
The perimeter of a square is the side multiplied by 4.
55 * 4 = 220;
220 * 2 = 440.
Answer: The sum of the two perimeters of the resulting squares is 440 cm.