A rectangle with sides of 8 m and 9 m revolves around the smaller side. find the lateral surface area.

The figure of rotation of the rectangle ABEO about its smaller side is a cylinder, the height of which is equal to the height of the rectangle, AB = 8 m, the radius of the base of the cylinder is equal to the width of the rectangle, AO = R = 9 m.

Then the lateral surface area is equal to: Sbok = 2 * π * R * AB = 2 * π * 9 * 8 = 144 * π m2.

Answer: The area of the lateral surface of the figure of revolution is 144 * π m2.



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