A rectangular parallelepiped with dimensions of 2 meters 3 meters 5 meters was cut into cubic decimeters
A rectangular parallelepiped with dimensions of 2 meters 3 meters 5 meters was cut into cubic decimeters and placed cubes on top of each other Find the height of the resulting parallelepiped.
1. By the condition of the problem, it is known that the dimensions of a rectangular parallelepiped are 2, 3 and 5 meters.
Volume units:
1 m³ = 1000 dm³.
2. We know that the volume V is equal to the product of three dimensions.
Let’s calculate what the volume is equal to at given values:
V = 2 m * 3 m * 5 m = 30 m³ = 30,000 dm³.
3. Divide into cubes with a volume of 1 dm³ and get
30,000 dm³: 1 dm³ = 30,000 cubes with an edge of 1 dm.
Put the cubes in a row and its length will be equal to 30,000 * 1 dm = 30,000 dm = 3000 m = 3 km.
Answer: The height of the resulting row is 3 km.