A rectangular pipe has an area of 120 cm², one leg is 14 cm shorter than the other. What is the hypotenuse of this triangle?

Let us denote one leg of this triangle by a, the other leg by b, and the hypotenuse by c. By hypothesis, a = b + 14.

Let’s find the legs of this triangle:

ab / 2 = 120;

(b + 14) * b = 120 * 2;

b ^ 2 + 14b – 240 = 0;

D = 14 ^ 2 + 4 * 240 = 196 + 960 = 1156; b> 0; =>; b = (- 14 + 34) / 2 = 10 (cm).

a = 10 + 14 = 24 (cm).

Find the hypotenuse of this triangle:

c ^ 2 = a ^ 2 + b ^ 2;

c ^ 2 = 24 ^ 2 + 10 ^ 2 = 576 + 100 = 676; c> 0; =>; c = 26 (cm).

Answer: The hypotenuse of this triangle is 26 cm.