A rectangular section, the perimeter of which is 42 m, was divided into 2 equal parts in the shape of a square.

A rectangular section, the perimeter of which is 42 m, was divided into 2 equal parts in the shape of a square. Find the area and perimeter.

Let us denote the length of one side of the rectangle by x, and the other by y. Considering that the opposite sides of the rectangle are equal, we get the perimeter of the rectangle:
2x + 2y = 42;
As a result of cutting, we got two equal squares, therefore, one of the sides of the rectangle is twice as large as the other:
2x = y;
Substituting into the perimeter equation, we find:
y + 2y = 3y = 42;
Then one of their sides is equal to y = 14, and the other is x = 14: 2 = 7.
The area of ​​each resulting square is 7×7 = 49 (sqm), the perimeter of each square is 7×4 = 28 (m), and the area of ​​the rectangle is 14×7 = 98 (sqm).
Answer: square area -49 sq.m; the perimeter of the square is 28 m, the area of ​​the rectangle is 98 sq. m.