A rectangular triangle with boats 6cm and 8cm rotates for the first time around the larger leg,

A rectangular triangle with boats 6cm and 8cm rotates for the first time around the larger leg, and the second around the smaller one. Determine the obtained geometric bodies and compare the areas of their lateral surfaces

We calculate the hypotenuse of a right-angled triangle using the Pythagorean theorem:

c = √ (6² + 8²) = √ (36 + 64) = √100 = 10 cm.

When the triangle rotates around the larger leg, a cone is obtained with a height of 8 cm, a radius of 6 cm and a generatrix of 10 cm.

Let’s calculate the lateral surface area:

Side = nRl (R – base radius, l – generatrix).

Side = n * 6 * 10 = 60p (cm²).

When the triangle rotates around the smaller leg, a cone is obtained with a height of 6 cm, a radius of 8 cm and a generatrix of 10 cm.

Let’s calculate the lateral surface area:

Side = n * 8 * 10 = 80p (cm²).

The lateral surface area of ​​the second cone is larger.



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