A regular hexagon ABCDEF is given. Prove that triangles ABC and DEF are equal.

Given:
hexagon ABCDEF is regular.
Prove that triangles ABC and DEF are equal.
Evidence:
1) Consider a regular hexagon ABCDEF. He has all sides and angles equal to each other by the definition of a regular hexagon;
2) Consider triangles ABC and DEF. They have BC = AB = DE = EF. Angle B = angle E. Therefore, the triangle ABC is equal to the triangle DEF along the dum sides and the angle between them. Q.E.D.



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