A regular quadrangular pyramid SABCD has an S-vertex. SC = 13, AC = 10 Find the height?
May 19, 2021 | education
| At the base of a regular pyramid is a square.
The diagonals of the square lying at the base of the pyramid, at the point of their intersection, are divided in half, then CO = AO = AC / 2 = 10/2 = 5 cm.
In a right-angled triangle SОС, we determine the length of the leg SO.
SO ^ 2 = SC ^ 2 – OC ^ 2 = 169 – 25 = 144.
SO = √144 = 12 cm.
Answer: The height of the pyramid is 12 cm.
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