A regular quadrangular pyramid SABCD has an S-vertex. SC = 13, AC = 10 Find the height?

At the base of a regular pyramid is a square.

The diagonals of the square lying at the base of the pyramid, at the point of their intersection, are divided in half, then CO = AO = AC / 2 = 10/2 = 5 cm.

In a right-angled triangle SОС, we determine the length of the leg SO.

SO ^ 2 = SC ^ 2 – OC ^ 2 = 169 – 25 = 144.

SO = √144 = 12 cm.

Answer: The height of the pyramid is 12 cm.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.